Chemistry – Stoichiometry - The mole and the Avogadro constant | e-Consult
Stoichiometry - The mole and the Avogadro constant (1 questions)
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Given:
- Mass of MgCO3 = 2.49 g
- Molar mass of MgCO3 = 12.01 (Mg) + 12.01 (C) + 3 * 16.00 (O) = 39.01 g/mol
Calculation:
Number of moles (n) =
n = 2.49 g / 39.01 g/mol = 0.0645 mol
Answer: The number of moles of magnesium carbonate is 0.0645 mol.