Physics – 1.7.1 Energy | e-Consult

Given:

• Mass (m) = 0.5 kg
• Initial height (h_i) = (Assume the height of the cliff is large enough so that the fall is significant. We are only given the bounce height.)
• Final height (h_f) = 1.2 m
• Acceleration due to gravity (g) = 9.8 m/s²

Equation: ΔE_p = m g Δh

Calculation:

The change in potential energy during the fall is equal to the change in height during the fall. We don't know the initial height, so we cannot calculate the exact change in potential energy during the fall. However, we know the change in potential energy during the rise.

Δh = h_i - h_f = h_i - 1.2 m

The change in potential energy during the rise is: ΔE_p = (0.5 kg) × (9.8 m/s²) × (1.2 m) = 5.88 J

Answer: The change in gravitational potential energy during the rise is 5.88 J. The change in potential energy during the fall is equal to the change in height during the fall, which is h_i - 1.2m. Without knowing h_i, we cannot give a numerical value for the fall.