Physics – 1.8 Pressure | e-Consult
1.8 Pressure (1 questions)
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We are given Δp = ρ g Δh. We need to find Δh, which is the depth, which is 1m.
We need to assume a density (ρ) for water. The density of water is approximately 1000 kg/m3.
Therefore, Δp = (1000 kg/m3) * (9.8 m/s2) * (1 m)
Δp = 9800 Pa = 9.8 x 103 Pa
Therefore, the change in pressure between the surface and 1m below the surface is 9.8 x 103 Pa.