Physics – 4.2.4 Resistance | e-Consult
4.2.4 Resistance (1 questions)
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Solution:
- Calculate the resistivity at 80°C: The resistivity at 80°C is given as ρ = 1.6 x 10-8 Ωm.
- Apply the resistance formula: R = ρL/A. We know the resistance at 20°C (R20 = 5.0 Ω), the resistivity at 20°C (ρ20 = 1.0 x 10-8 Ωm), and the resistivity at 80°C (ρ80 = 1.6 x 10-8 Ωm). We can assume the length and cross-sectional area remain constant. Therefore, we can write: R80 = ρ80L/A. We also know R20 = ρ20L/A. Dividing the two equations: R80 / R20 = (ρ80L/A) / (ρ20L/A) = ρ80 / ρ20.
- Calculate R80: R80 = R20 * (ρ80 / ρ20) = 5.0 Ω * (1.6 x 10-8 Ωm / 1.0 x 10-8 Ωm) = 8.0 Ω.
Answer: The new resistance of the conductor is 8.0 Ω.