Physics – 4.5.4 Force on a current-carrying conductor | e-Consult
4.5.4 Force on a current-carrying conductor (1 questions)
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When the velocity of a charged particle is parallel to the magnetic field, the magnetic force is zero. This is because sin(90°) = 1, and the force is proportional to sinθ. Therefore, F = qvBsinθ = qvBsin(90°) = qvB.
In this case, the velocity (v) is parallel to the magnetic field (B), so θ = 90 degrees and sin(90°) = 1.
Therefore, F = (-1.60 x 10-19 C) * (2.0 x 107 m/s) * (0.5 T)
F = -1.60 x 10-18 N
The magnitude of the force is 1.60 x 10-18 N, and the direction is parallel to the magnetic field (because the charge is negative).