Additional Mathematics – Trigonometry | e-Consult
Trigonometry (1 questions)
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Answer 1
- Amplitude = 2
- Period = \(\displaystyle\frac{2\pi}{3}\)
- Phase shift = 0 (no horizontal translation)
- Vertical shift = –1
| Maximum y = +1 at x = \(\frac{\pi}{6}+k\frac{2\pi}{3}\) (k = 0,1,2… within domain → x = π/6, 5π/6, 3π/2) |
| Minimum y = −3 at x = \(\frac{5\pi}{6}+k\frac{2\pi}{3}\) (k = 0,1,2… within domain → x = 5π/6, 7π/6, 11π/6) |
The sketch shows a sinusoid of height 2, shifted down by 1, completing three full cycles between 0 and 2π.