Computer Science – 15.2 Boolean Algebra and Logic Circuits | e-Consult
15.2 Boolean Algebra and Logic Circuits (1 questions)
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Answer:
The Boolean expression for the function can be represented using a 3-variable Karnaugh map. The map will look like this:
| 000 | 001 | 010 | 011 |
| 100 | 101 | 110 | 111 |
We can group the '1's as follows:
- A 000 and A 001 can be grouped.
- A 010 and A 011 can be grouped.
- A 101 and A 110 can be grouped.
- A 111 remains as a single '1'.
Grouping these gives us the simplified expression: F = (A & ~B & ~C) | (~A & ~B & C) | (A & B & ~C) | (A & B & C)
Alternatively, this can be expressed as: F = A'C' + A'BC + AB'C + ABC