Chemistry – Inorganic chemistry | e-Consult
Inorganic chemistry (1 questions)
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Here are the half-equations and oxidation states for the given reactions:
- Copper(I) oxide reacting with acid: CuO(s) + 2H+(aq) → Cu2+(aq) + H2O(l)
- Oxidation state of copper: +2
- Copper(II) oxide reacting with reducing agents: CuO(s) + 2e- → Cu(s)
- Oxidation state of copper: +2
- Copper reacting with oxygen: 2Cu(s) + O2(g) → 2CuO(s)
- Oxidation state of copper: +2