Kinematics of motion in 2 dimensions: displacement, velocity, acceleration, projectile motion
Mechanics (M2) – Kinematics in 2D 🚀
1️⃣ Displacement
Displacement is the straight‑line vector from the start point to the end point. It has both magnitude and direction.
Analogy: Imagine walking from your home to a friend's house. The distance you actually walk (path length) is different from the straight‑line distance between the two houses.
Formula: $\displaystyle \mathbf{s}= \mathbf{r}_f-\mathbf{r}_i$
- Vector notation: $\mathbf{s} = (x_f-x_i,\, y_f-y_i)$
- Magnitude: $|\mathbf{s}| = \sqrt{(x_f-x_i)^2+(y_f-y_i)^2}$
2️⃣ Velocity
Velocity is the rate of change of displacement. It is a vector.
Analogy: Think of a cyclist who pedals faster – their velocity increases.
Formula (instantaneous): $\displaystyle \mathbf{v} = \frac{d\mathbf{s}}{dt}$
For constant velocity: $\displaystyle \mathbf{v} = \frac{\mathbf{s}}{t}$
- Component form: $v_x = \frac{dx}{dt}$, $v_y = \frac{dy}{dt}$
- Magnitude: $|\mathbf{v}| = \sqrt{v_x^2+v_y^2}$
3️⃣ Acceleration
Acceleration is the rate of change of velocity.
Analogy: If you press the gas pedal harder, the car’s acceleration increases.
Formula (instantaneous): $\displaystyle \mathbf{a} = \frac{d\mathbf{v}}{dt}$
For constant acceleration: $\displaystyle \mathbf{a} = \frac{\Delta\mathbf{v}}{\Delta t}$
- Component form: $a_x = \frac{dv_x}{dt}$, $a_y = \frac{dv_y}{dt}$
- Magnitude: $|\mathbf{a}| = \sqrt{a_x^2+a_y^2}$
4️⃣ Projectile Motion 🎯
A projectile follows a parabolic path under the influence of gravity alone (ignoring air resistance).
Key assumptions:
- Initial position at the origin: $\mathbf{r}_0 = (0,0)$
- Initial velocity: $\mathbf{v}_0 = (v_{0x}, v_{0y})$
- Acceleration: $\mathbf{a} = (0, -g)$, where $g \approx 9.81\,\text{m/s}^2$
Equations of motion:
- Horizontal: $x = v_{0x}\,t$
- Vertical: $y = v_{0y}\,t - \tfrac{1}{2}gt^2$
- Velocity components: $v_x = v_{0x}$, $v_y = v_{0y} - g t$
Launch angle $\theta$ gives: $v_{0x} = v_0\cos\theta$, $v_{0y} = v_0\sin\theta$.
| Parameter | Symbol | Formula | Example |
|---|---|---|---|
| Time of flight | $T$ | $T = \frac{2v_0\sin\theta}{g}$ | $v_0=20\,\text{m/s},\;\theta=45^\circ \Rightarrow T \approx 2.88\,\text{s}$ |
| Maximum height | $H$ | $H = \frac{v_0^2\sin^2\theta}{2g}$ | $v_0=20\,\text{m/s},\;\theta=45^\circ \Rightarrow H \approx 20.4\,\text{m}$ |
| Range | $R$ | $R = \frac{v_0^2\sin 2\theta}{g}$ | $v_0=20\,\text{m/s},\;\theta=45^\circ \Rightarrow R \approx 40.8\,\text{m}$ |
Key Take‑aways 📚
- Displacement is a vector; use components.
- Velocity and acceleration are derivatives of displacement and velocity respectively.
- In projectile motion, horizontal motion is uniform; vertical motion is uniformly accelerated.
- Always check units and keep track of signs (positive upwards, negative downwards).
Revision
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