Recall and use the equation for the change in pressure beneath the surface of a liquid Δp = ρ g Δh

1.8 Pressure

Objective

Recall and use the equation for the change in pressure beneath the surface of a liquid: Δp = ρ g Δh 💧

What is Pressure?

Pressure is the force applied per unit area. Think of it like the push you feel when you press your palm against a wall. The deeper you go under water, the more “push” you feel because the water above is heavier. 📏

Key Equation

The change in pressure with depth is given by:

$$\Delta p = \rho g \Delta h$$

  • ρ (rho) – Density of the liquid (kg m⁻³)
  • g – Acceleration due to gravity (≈9.8 m s⁻²)
  • Δh – Change in depth (m)

Units & Symbols

Symbol Unit Example
ρ kg m⁻³ 1000 (water)
g m s⁻² 9.8
Δh m 5
Δp Pa (N m⁻²) 49000

Analogy: The Slinky in a Bottle

Imagine a slinky inside a bottle. When you push the top of the slinky down, the bottom feels a stronger push because the slinky above is heavier. Similarly, the deeper you go in a liquid, the more weight of liquid sits above you, increasing pressure. 🎈

Example Problem

  1. Water depth: Δh = 5 m
  2. Density of water: ρ = 1000 kg m⁻³
  3. Gravity: g = 9.8 m s⁻²
  4. Calculate Δp.

Using the formula:

$$\Delta p = 1000 \times 9.8 \times 5 = 49\,000 \text{ Pa}$$

So at 5 m depth, the pressure is 49 kPa higher than at the surface. 🚤

Quick Quiz

  • What happens to Δp if you double the depth Δh? 🤔
  • How would the pressure change if you used a liquid with half the density of water? 💧
  • Calculate the pressure increase at 10 m depth in seawater (ρ ≈ 1025 kg m⁻³). 📐

Revision

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