Use count rate measured in counts/s or counts/minute
5.2.1 Detection of Radioactivity
What is a Count Rate?
When a radioactive source emits particles, a detector records how many particles hit it over a given time. The count rate tells us how many counts are recorded per unit time.
Common units:
- $\text{counts per second (cps)}$
- $\text{counts per minute (cpm)}$
📈 Analogy: Think of a rain gauge. The number of raindrops that fall in one second is like cps, while the number that fall in a minute is like cpm.
Calculating Count Rate
If a detector records C counts in a time interval t, the count rate R is:
$R = \dfrac{C}{t}$
Example:
- 20 counts in 10 seconds → $R = 20/10 = 2$ cps
- 120 counts in 2 minutes → $R = 120/(2\times60) = 1$ cps
💡 Tip: Always check the units of time before dividing.
Common Detectors
- Geiger–Müller tube – counts individual particles.
- Scintillation counter – flashes light when a particle hits a crystal.
- Semiconductor detector – measures charge produced by particles.
Each detector gives a count rate that can be converted to activity (decays per second) if the detection efficiency is known.
Example Table: Counts vs. Time
| Time (s) | Counts (C) | Count Rate (cps) |
|---|---|---|
| 10 | 25 | 2.5 |
| 30 | 75 | 2.5 |
| 60 | 150 | 2.5 |
📊 Notice the count rate stays constant – this indicates a stable source.
Exam Tips
- Always state the unit of your count rate (cps or cpm).
- If a problem gives counts in minutes, convert to seconds before calculating cps.
- Check that your answer makes sense: a higher number of counts in a shorter time → higher cps.
- Remember that the count rate is an average over the time interval; short bursts can still give a high average.
?? Quick Check: If you get 500 counts in 5 minutes, what is the cps?
Solution: $500/(5\times60)=1.67$ cps.
Revision
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