Differentiate products and quotients of functions using the product and quotient rules

Calculus: Product & Quotient Rules

Objective

Learn how to differentiate products and quotients of functions using the product rule and quotient rule so you can tackle any IGCSE Additional Mathematics question with confidence. 🚀

The Product Rule

Imagine two friends A and B dancing together. The speed of the dance (the derivative) depends on how fast each friend moves and how their movements combine.

Mathematically, if f(x) and g(x) are differentiable, then:

Product Rule: $(f\cdot g)' = f'\cdot g + f\cdot g'$

  1. Differentiate f(x)f'(x).
  2. Differentiate g(x)g'(x).
  3. Multiply the first derivative by the other function: f'(x)·g(x).
  4. Multiply the second derivative by the first function: f(x)·g'(x).
  5. Add the two results together.

Example:

Find $(x^2\sin x)'$.

Let f(x)=x^2, g(x)=\sin x.

Then f'(x)=2x, g'(x)=\cos x.

Apply the rule:

$(x^2\sin x)' = 2x\sin x + x^2\cos x$

The Quotient Rule

Think of a recipe where you divide a mixture into portions. The rate of change of the ratio depends on both the numerator and denominator.

For differentiable functions f(x) and g(x) (with g(x)≠0):

Quotient Rule: $\displaystyle \left(\frac{f}{g}\right)' = \frac{f'\,g - f\,g'}{g^2}$

  1. Differentiate the numerator: f'(x).
  2. Differentiate the denominator: g'(x).
  3. Compute f'(x)·g(x) and f(x)·g'(x).
  4. Subtract: f'(x)·g(x) - f(x)·g'(x).
  5. Divide by [g(x)]².

Example:

Find $\left(\frac{x}{\sqrt{x}}\right)'$.

Let f(x)=x, g(x)=x^{1/2}.

Then f'(x)=1, g'(x)=\frac{1}{2}x^{-1/2}.

Apply the rule:

$\displaystyle \left(\frac{x}{\sqrt{x}}\right)' = \frac{1\cdot x^{1/2} - x\cdot \frac{1}{2}x^{-1/2}}{(x^{1/2})^2} = \frac{x^{1/2} - \frac{1}{2}x^{1/2}}{x} = \frac{\frac{1}{2}x^{1/2}}{x} = \frac{1}{2}x^{-1/2}$

Exam Tips & Common Pitfalls

  • ?? Check your work: After applying the rule, simplify the expression to avoid messy answers.
  • ?? Remember the order: For the product rule, it’s “f′·g + f·g′”. For the quotient rule, it’s “f′·g – f·g′” over “g²”.
  • Don’t forget the minus sign: In the quotient rule, the second term is subtracted.
  • Watch out for zero denominators: The quotient rule only applies when g(x) ≠ 0.
  • 🔍 Practice with different functions: Try polynomials, trigonometric, exponential, and logarithmic functions to build confidence.
  • 🧩 Use the “rule of thumb”: If you’re unsure, rewrite the function as a product (e.g., f/g = f·g⁻¹) and apply the product rule with the chain rule on g⁻¹.

Quick Check

Differentiate $\frac{e^x}{x^2}$:

f(x)=e^x, g(x)=x² → f'=e^x, g'=2x.

Result: $\displaystyle \frac{e^x·x^2 - e^x·2x}{x^4} = \frac{e^x(x^2-2x)}{x^4} = e^x\frac{x-2}{x^3}$

Revision

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