define and use the terms mass defect and binding energy

Mass Defect and Nuclear Binding Energy

🔬 Mass defect is the difference between the mass of a nucleus and the sum of the masses of its individual protons and neutrons.
💡 Binding energy is the energy equivalent of that mass difference, calculated using Einstein’s famous equation $E = mc^2$.

Why Does Mass Defect Happen?

Think of a team of friends (protons + neutrons) who decide to join together to form a stronger bond. When they bond, the team becomes a bit lighter because some of the “extra weight” (energy) is released into the world as light or radiation. That lost weight is the mass defect.

Calculating Mass Defect

  1. Find the mass of each proton ($m_p$) and neutron ($m_n$).
  2. Multiply by the number of each in the nucleus: $Z \times m_p$ and $N \times m_n$.
  3. Sum them: $M_{\text{separate}} = Z\,m_p + N\,m_n$.
  4. Subtract the actual nuclear mass ($M_{\text{nucleus}}$):

$$\Delta m = M_{\text{separate}} - M_{\text{nucleus}}$$

From Mass Defect to Binding Energy

Use Einstein’s equation to convert the mass defect into energy:
$$E_b = \Delta m \, c^2$$
Here, $E_b$ is the binding energy of the nucleus. It tells us how much energy would be required to break the nucleus apart.

Example: Helium‑4 Nucleus

Item Value (u)
Proton mass ($m_p$) 1.007276
Neutron mass ($m_n$) 1.008665
Number of protons ($Z$) 2
Number of neutrons ($N$) 2
Separate mass ($M_{\text{separate}}$) $2\times1.007276 + 2\times1.008665 = 4.031882$
Actual nuclear mass ($M_{\text{nucleus}}$) 4.001506
Mass defect ($\Delta m$) $0.030376$ u
Binding energy ($E_b$) $28.3$ MeV

Exam Tip 💡

• Remember the order of operations: first calculate the separate mass, then subtract the actual nuclear mass to get the mass defect.
• Convert the mass defect to binding energy using $E = \Delta m\,c^2$.
• Check units: 1 atomic mass unit (u) ≈ 931.5 MeV/$c^2$.
• Practice with different nuclei (e.g., $^{12}$C, $^{56}$Fe) to see how binding energy per nucleon changes.
• In multiple‑choice questions, look for the answer that matches the magnitude of the binding energy (tens of MeV for light nuclei, hundreds for heavy nuclei).

Revision

Log in to practice.

8 views 0 suggestions