understand that a photon is a quantum of electromagnetic energy
Energy and Momentum of a Photon
📚 What is a photon? A photon is a tiny, indivisible packet of electromagnetic energy. Think of it as a “light bullet” that travels at the speed of light, $c = 3.0 \times 10^8 \,\text{m/s}$.
Energy of a Photon
The energy of a single photon is given by the famous equation:
$E = hu$
where $h = 6.63 \times 10^{-34}\,\text{J·s}$ is Planck’s constant and $u$ is the frequency of the light.
Because frequency and wavelength are related by $c = \lambda u$, we can also write:
$E = \frac{hc}{\lambda}$
So, the shorter the wavelength, the higher the energy.
Momentum of a Photon
Even though photons have no mass, they still carry momentum:
$p = \frac{h}{\lambda}$
Think of a photon as a tiny “push” that can change the motion of an object, like a gentle breeze that nudges a feather.
Quick Reference Table
| Property | Formula | Units |
|---|---|---|
| Energy | $E = hu = \dfrac{hc}{\lambda}$ | Joules (J) |
| Momentum | $p = \dfrac{h}{\lambda}$ | kg·m/s |
How to Calculate Photon Energy (Step‑by‑Step)
- Find the wavelength $\lambda$ of the light (e.g., $\lambda = 500\,\text{nm}$).
- Convert $\lambda$ to metres: $500\,\text{nm} = 5.00 \times 10^{-7}\,\text{m}$.
- Use $E = \dfrac{hc}{\lambda}$ with $h = 6.63 \times 10^{-34}\,\text{J·s}$ and $c = 3.00 \times 10^8\,\text{m/s}$.
- Calculate: $E = \dfrac{(6.63 \times 10^{-34})(3.00 \times 10^8)}{5.00 \times 10^{-7}} \approx 3.98 \times 10^{-19}\,\text{J}$.
- Convert to electron‑volts if needed: $1\,\text{eV} = 1.60 \times 10^{-19}\,\text{J}$ → $E \approx 2.49\,\text{eV}$.
Exam Tip Box
🔍 Remember: In exam questions you’ll often be given either wavelength or frequency. Use the appropriate formula:
- If given $u$, use $E = hu$.
- If given $\lambda$, use $E = \dfrac{hc}{\lambda}$.
For momentum, always use $p = \dfrac{h}{\lambda}$. No mass needed!
Check units carefully – energy in joules or eV, momentum in kg·m/s.
Real‑World Analogy: Light as a “Photon Train”
Imagine a train where each car is a photon. The train moves at light speed. The energy of the train depends on how many cars (photons) it has and how fast each car is moving (frequency). The momentum is like the push each car gives to the train’s front.
When the train stops (light is absorbed), the energy and momentum are transferred to the material, causing effects like heating or the photoelectric effect.
Key Takeaways
- Photons are quantum packets of electromagnetic energy.
- Energy: $E = hu = \dfrac{hc}{\lambda}$.
- Momentum: $p = \dfrac{h}{\lambda}$.
- Shorter wavelength = higher energy and momentum.
- Use the right formula based on the given data.
Revision
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