understand that a photon has momentum and that the momentum is given by p = E / c
Energy and Momentum of a Photon 🎓
What is a Photon? 🔬
A photon is a tiny packet of light energy that travels at the speed of light, c = 3 × 10⁸ m/s. Think of it like a miniature “light bullet” that can move through space without any mass, but still carries energy and can push on objects when it hits them. ✨
Energy of a Photon 💡
The energy of a photon is related to its frequency (ν) or wavelength (λ) by Planck’s equation:
$E = hu = \dfrac{hc}{\lambda}$
Where h is Planck’s constant (6.626 × 10⁻³⁴ J·s). If you know the wavelength, you can find the energy, and vice‑versa. 📐
Momentum of a Photon 🚀
Even though a photon has no mass, it still carries momentum. Imagine a tiny snowball (the photon) rolling into a wall; the wall feels a small push. The momentum p of a photon is given by:
$p = \dfrac{E}{c}$
Because E = hc/λ, we can also write:
$p = \dfrac{h}{\lambda}$
So the shorter the wavelength, the larger the momentum. 🌈
Quick Example 📐
- Take a green light photon with λ = 500 nm = 5.00 × 10⁻⁷ m.
- Compute its momentum:
$p = \dfrac{h}{\lambda} = \dfrac{6.626\times10^{-34}\,\text{J·s}}{5.00\times10^{-7}\,\text{m}} \approx 1.33\times10^{-27}\,\text{kg·m/s}$
- Notice that this is a very tiny momentum, but it is real and measurable in experiments like the photoelectric effect.
Key Relationships in a Table 📊
| Quantity | Symbol | Formula | Units |
|---|---|---|---|
| Energy | $E$ | $E = \dfrac{hc}{\lambda}$ | Joules (J) |
| Momentum | $p$ | $p = \dfrac{E}{c} = \dfrac{h}{\lambda}$ | kg·m/s |
| Frequency | $u$ | $E = hu$ | Hz |
Exam Tip 📚
- Always keep c = 3.00 × 10⁸ m/s in mind when converting between energy and momentum.
- When a question gives wavelength, use $p = h/\lambda$ directly – no need to find energy first.
- Check units: J for energy, kg·m/s for momentum, m for wavelength.
- Remember that photons are massless, so p = mv does not apply.
Quick Flashcard 🧠
Question: A photon has a wavelength of 400 nm. What is its momentum?
Answer: $p = \dfrac{h}{\lambda} = \dfrac{6.626\times10^{-34}}{4.00\times10^{-7}} \approx 1.66\times10^{-27}\,\text{kg·m/s}$.
Revision
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